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13122013233 = 37624857773
BaseRepresentation
bin11000011100010001…
…00000100000110001
31020212111101100011010
430032020200200301
5203333213410413
610010030141133
7643114162230
oct141610404061
936774340133
1013122013233
11562404183a
1226626517a9
131311752094
148c6a4ab17
1551c003dc3
hex30e220831

13122013233 has 8 divisors (see below), whose sum is σ = 19995448768. Its totient is φ = 7498293264.

The previous prime is 13122013217. The next prime is 13122013241. The reversal of 13122013233 is 33231022131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13122013233 - 24 = 13122013217 is a prime.

It is a super-2 number, since 2×131220132332 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 624857773 = 13122013233 / (1 + 3 + 1 + 2 + 2 + 0 + 1 + 3 + 2 + 3 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13122013283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312428866 + ... + 312428907.

It is an arithmetic number, because the mean of its divisors is an integer number (2499431096).

Almost surely, 213122013233 is an apocalyptic number.

It is an amenable number.

13122013233 is a deficient number, since it is larger than the sum of its proper divisors (6873435535).

13122013233 is an equidigital number, since it uses as much as digits as its factorization.

13122013233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 624857783.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13122013233 its reverse (33231022131), we get a palindrome (46353035364).

It can be divided in two parts, 131220 and 13233, that added together give a triangular number (144453 = T537).

The spelling of 13122013233 in words is "thirteen billion, one hundred twenty-two million, thirteen thousand, two hundred thirty-three".

Divisors: 1 3 7 21 624857773 1874573319 4374004411 13122013233