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131220143 is a prime number
BaseRepresentation
bin1111101001001…
…00001010101111
3100010220200012022
413310210022233
5232043021033
621004300355
73152232005
oct764441257
9303820168
10131220143
11680856aa
1237b416bb
1321254c72
14135daa75
15b7c0098
hex7d242af

131220143 has 2 divisors, whose sum is σ = 131220144. Its totient is φ = 131220142.

The previous prime is 131220101. The next prime is 131220149. The reversal of 131220143 is 341022131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131220143 - 26 = 131220079 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131220149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610071 + 65610072.

It is an arithmetic number, because the mean of its divisors is an integer number (65610072).

Almost surely, 2131220143 is an apocalyptic number.

131220143 is a deficient number, since it is larger than the sum of its proper divisors (1).

131220143 is an equidigital number, since it uses as much as digits as its factorization.

131220143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 131220143 is about 11455.1360969654. The cubic root of 131220143 is about 508.1596401885.

Adding to 131220143 its reverse (341022131), we get a palindrome (472242274).

The spelling of 131220143 in words is "one hundred thirty-one million, two hundred twenty thousand, one hundred forty-three".