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13122022 = 26561011
BaseRepresentation
bin110010000011…
…100111100110
3220200200000211
4302003213212
511324401042
61145130034
7216351424
oct62034746
926620024
1013122022
117452851
12448991a
132945914
141a58114
151243017
hexc839e6

13122022 has 4 divisors (see below), whose sum is σ = 19683036. Its totient is φ = 6561010.

The previous prime is 13122001. The next prime is 13122037. The reversal of 13122022 is 22022131.

13122022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131220222 = 344374922736968, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13121993 and 13122011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280504 + ... + 3280507.

It is an arithmetic number, because the mean of its divisors is an integer number (4920759).

Almost surely, 213122022 is an apocalyptic number.

13122022 is a deficient number, since it is larger than the sum of its proper divisors (6561014).

13122022 is an equidigital number, since it uses as much as digits as its factorization.

13122022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6561013.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 13122022 is about 3622.4331601839. The cubic root of 13122022 is about 235.8668572947.

Adding to 13122022 its reverse (22022131), we get a palindrome (35144153).

It can be divided in two parts, 131 and 22022, that multiplied together give a palindrome (2884882).

The spelling of 13122022 in words is "thirteen million, one hundred twenty-two thousand, twenty-two".

Divisors: 1 2 6561011 13122022