Base | Representation |
---|---|
bin | 111101000110101011… |
… | …0100100010001000010 |
3 | 110112200222120012010012 |
4 | 1322031112210101002 |
5 | 4122214423201200 |
6 | 140140515104522 |
7 | 12323524014452 |
oct | 1721526442102 |
9 | 415628505105 |
10 | 131220522050 |
11 | 50717622442 |
12 | 215215a2142 |
13 | c4b2a02c27 |
14 | 64cb61bd62 |
15 | 36300a4a35 |
hex | 1e8d5a4442 |
131220522050 has 18 divisors (see below), whose sum is σ = 244074935403. Its totient is φ = 52487184240.
The previous prime is 131220522031. The next prime is 131220522067. The reversal of 131220522050 is 50225022131.
131220522050 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 5 ways, for example, as 10011403249 + 121209118801 = 100057^2 + 348151^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=256145.
It is a Duffinian number.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 2535836 + ... + 2587064.
Almost surely, 2131220522050 is an apocalyptic number.
131220522050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131220522050 is a deficient number, since it is larger than the sum of its proper divisors (112854413353).
131220522050 is an frugal number, since it uses more digits than its factorization.
131220522050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102470 (or 51236 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 131220522050 its reverse (50225022131), we get a palindrome (181445544181).
The spelling of 131220522050 in words is "one hundred thirty-one billion, two hundred twenty million, five hundred twenty-two thousand, fifty".
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