Base | Representation |
---|---|
bin | 10011000110000101111… |
… | …000111110100001100101 |
3 | 11122110001021010100110002 |
4 | 103012011320332201211 |
5 | 132444402100044143 |
6 | 2442453242511045 |
7 | 163542551165111 |
oct | 23060570764145 |
9 | 4573037110402 |
10 | 1312211331173 |
11 | 4665620a6026 |
12 | 192394b05485 |
13 | 96982c829a2 |
14 | 47723298741 |
15 | 24200edc5b8 |
hex | 13185e3e865 |
1312211331173 has 2 divisors, whose sum is σ = 1312211331174. Its totient is φ = 1312211331172.
The previous prime is 1312211331169. The next prime is 1312211331203. The reversal of 1312211331173 is 3711331122131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 975576970369 + 336634360804 = 987713^2 + 580202^2 .
It is an emirp because it is prime and its reverse (3711331122131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312211331173 - 22 = 1312211331169 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312211331103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656105665586 + 656105665587.
It is an arithmetic number, because the mean of its divisors is an integer number (656105665587).
Almost surely, 21312211331173 is an apocalyptic number.
It is an amenable number.
1312211331173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312211331173 is an equidigital number, since it uses as much as digits as its factorization.
1312211331173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2268, while the sum is 29.
The spelling of 1312211331173 in words is "one trillion, three hundred twelve billion, two hundred eleven million, three hundred thirty-one thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •