Base | Representation |
---|---|
bin | 10011000110000101111… |
… | …000111110100010000011 |
3 | 11122110001021010100111012 |
4 | 103012011320332202003 |
5 | 132444402100044303 |
6 | 2442453242511135 |
7 | 163542551165153 |
oct | 23060570764203 |
9 | 4573037110435 |
10 | 1312211331203 |
11 | 4665620a6053 |
12 | 192394b054ab |
13 | 96982c829c6 |
14 | 47723298763 |
15 | 24200edc5d8 |
hex | 13185e3e883 |
1312211331203 has 2 divisors, whose sum is σ = 1312211331204. Its totient is φ = 1312211331202.
The previous prime is 1312211331173. The next prime is 1312211331217. The reversal of 1312211331203 is 3021331122131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312211331203 - 216 = 1312211265667 is a prime.
It is a super-2 number, since 2×13122113312032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312211331103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656105665601 + 656105665602.
It is an arithmetic number, because the mean of its divisors is an integer number (656105665602).
Almost surely, 21312211331203 is an apocalyptic number.
1312211331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312211331203 is an equidigital number, since it uses as much as digits as its factorization.
1312211331203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1312211331203 its reverse (3021331122131), we get a palindrome (4333542453334).
The spelling of 1312211331203 in words is "one trillion, three hundred twelve billion, two hundred eleven million, three hundred thirty-one thousand, two hundred three".
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