Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …110010000010011001101 |
3 | 11122110001221111211022001 |
4 | 103012012132100103031 |
5 | 132444412100301214 |
6 | 2442454232152301 |
7 | 163543030225234 |
oct | 23060636202315 |
9 | 4573057454261 |
10 | 1312221103309 |
11 | 46656766aa76 |
12 | 192398238691 |
13 | 96984cc490c |
14 | 477246bdb1b |
15 | 24201cbcc74 |
hex | 131867904cd |
1312221103309 has 2 divisors, whose sum is σ = 1312221103310. Its totient is φ = 1312221103308.
The previous prime is 1312221103307. The next prime is 1312221103367. The reversal of 1312221103309 is 9033011222131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 762473000809 + 549748102500 = 873197^2 + 741450^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312221103309 - 21 = 1312221103307 is a prime.
Together with 1312221103307, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312221103301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110551654 + 656110551655.
It is an arithmetic number, because the mean of its divisors is an integer number (656110551655).
Almost surely, 21312221103309 is an apocalyptic number.
It is an amenable number.
1312221103309 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312221103309 is an equidigital number, since it uses as much as digits as its factorization.
1312221103309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 1312221103309 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, one hundred three thousand, three hundred nine".
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