Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …111000000011001010111 |
3 | 11122110001221212211112102 |
4 | 103012012133000121113 |
5 | 132444412123102221 |
6 | 2442454240312315 |
7 | 163543032005465 |
oct | 23060637003127 |
9 | 4573057784472 |
10 | 1312221300311 |
11 | 466567794a89 |
12 | 19239831269b |
13 | 9698506349c |
14 | 47724731835 |
15 | 24201d0b30b |
hex | 131867c0657 |
1312221300311 has 4 divisors (see below), whose sum is σ = 1312227345000. Its totient is φ = 1312215255624.
The previous prime is 1312221300307. The next prime is 1312221300347. The reversal of 1312221300311 is 1130031222131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312221300311 - 22 = 1312221300307 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312221800311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2684096 + ... + 3135093.
It is an arithmetic number, because the mean of its divisors is an integer number (328056836250).
Almost surely, 21312221300311 is an apocalyptic number.
1312221300311 is a deficient number, since it is larger than the sum of its proper divisors (6044689).
1312221300311 is an equidigital number, since it uses as much as digits as its factorization.
1312221300311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6044688.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1312221300311 its reverse (1130031222131), we get a palindrome (2442252522442).
The spelling of 1312221300311 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, three hundred thousand, three hundred eleven".
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