Base | Representation |
---|---|
bin | 111101000110101110… |
… | …1000010110110111111 |
3 | 110112201002202110120111 |
4 | 1322031131002312333 |
5 | 4122220342021343 |
6 | 140141015330451 |
7 | 12323544316423 |
oct | 1721535026677 |
9 | 415632673514 |
10 | 131222220223 |
11 | 50718582296 |
12 | 21522080a27 |
13 | c4b3178b73 |
14 | 64cb940b83 |
15 | 36302dcc9d |
hex | 1e8d742dbf |
131222220223 has 2 divisors, whose sum is σ = 131222220224. Its totient is φ = 131222220222.
The previous prime is 131222220211. The next prime is 131222220281. The reversal of 131222220223 is 322022222131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131222220223 - 213 = 131222212031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131222220194 and 131222220203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131222224223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611110111 + 65611110112.
It is an arithmetic number, because the mean of its divisors is an integer number (65611110112).
Almost surely, 2131222220223 is an apocalyptic number.
131222220223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222220223 is an equidigital number, since it uses as much as digits as its factorization.
131222220223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 131222220223 its reverse (322022222131), we get a palindrome (453244442354).
The spelling of 131222220223 in words is "one hundred thirty-one billion, two hundred twenty-two million, two hundred twenty thousand, two hundred twenty-three".
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