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13122222103 is a prime number
BaseRepresentation
bin11000011100010010…
…10011100000010111
31020212111202221200001
430032021103200113
5203333242101403
610010034432131
7643116022204
oct141611234027
936774687601
1013122222103
115624174761
122662732647
1313117c6183
148c6aa2cab
1551c045c1d
hex30e253817

13122222103 has 2 divisors, whose sum is σ = 13122222104. Its totient is φ = 13122222102.

The previous prime is 13122222031. The next prime is 13122222107. The reversal of 13122222103 is 30122222131.

Together with previous prime (13122222031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (30122222131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122222103 - 221 = 13120124951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122222107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561111051 + 6561111052.

It is an arithmetic number, because the mean of its divisors is an integer number (6561111052).

Almost surely, 213122222103 is an apocalyptic number.

13122222103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122222103 is an equidigital number, since it uses as much as digits as its factorization.

13122222103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13122222103 its reverse (30122222131), we get a palindrome (43244444234).

It can be divided in two parts, 13122 and 222103, that added together give a square (235225 = 4852).

The spelling of 13122222103 in words is "thirteen billion, one hundred twenty-two million, two hundred twenty-two thousand, one hundred three".