Base | Representation |
---|---|
bin | 1011111011110100000111… |
… | …1011000110011101110111 |
3 | 1201110110202211212211101112 |
4 | 2332331001323012131313 |
5 | 3204443312130220203 |
6 | 43524134133145235 |
7 | 2523023055666332 |
oct | 276750173063567 |
9 | 51413684784345 |
10 | 13122231101303 |
11 | 41aa11a3a7295 |
12 | 157b21478b21b |
13 | 74256217346c |
14 | 3351957c3619 |
15 | 17b51544e6d8 |
hex | bef41ec6777 |
13122231101303 has 2 divisors, whose sum is σ = 13122231101304. Its totient is φ = 13122231101302.
The previous prime is 13122231101297. The next prime is 13122231101333. The reversal of 13122231101303 is 30310113222131.
It is a weak prime.
It is an emirp because it is prime and its reverse (30310113222131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13122231101303 - 28 = 13122231101047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122231101333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561115550651 + 6561115550652.
It is an arithmetic number, because the mean of its divisors is an integer number (6561115550652).
Almost surely, 213122231101303 is an apocalyptic number.
13122231101303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122231101303 is an equidigital number, since it uses as much as digits as its factorization.
13122231101303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13122231101303 its reverse (30310113222131), we get a palindrome (43432344323434).
The spelling of 13122231101303 in words is "thirteen trillion, one hundred twenty-two billion, two hundred thirty-one million, one hundred one thousand, three hundred three".
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