1312230000101 has 4 divisors (see below), whose sum is σ = 1312232522400. Its totient is φ = 1312227477804.

The previous prime is 1312230000089. The next prime is 1312230000113. The reversal of 1312230000101 is 1010000322131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1312230000089) and next prime (1312230000113).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312230000101 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312230003101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160691 + ... + 1627968.

It is an arithmetic number, because the mean of its divisors is an integer number (328058130600).

Almost surely, 2^{1312230000101} is an apocalyptic number.

It is an amenable number.

1312230000101 is a deficient number, since it is larger than the sum of its proper divisors (2522299).

1312230000101 is an equidigital number, since it uses as much as digits as its factorization.

1312230000101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2522298.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1312230000101 its reverse (1010000322131), we get a palindrome (2322230322232).

The spelling of 1312230000101 in words is "one trillion, three hundred twelve billion, two hundred thirty million, one hundred one", and thus it is an aban number.