Base | Representation |
---|---|
bin | 1011111011110100011000… |
… | …0011100100111101111111 |
3 | 1201110110221200100012120120 |
4 | 2332331012003210331333 |
5 | 3204443432402313010 |
6 | 43524145051150023 |
7 | 2523024560205360 |
oct | 276750603447577 |
9 | 51413850305516 |
10 | 13122300432255 |
11 | 41aa1555506a3 |
12 | 157b233a45313 |
13 | 7425736395b1 |
14 | 3351a0aadb67 |
15 | 17b51b596e70 |
hex | bef460e4f7f |
13122300432255 has 32 divisors (see below), whose sum is σ = 23995205351424. Its totient is φ = 5998730486016.
The previous prime is 13122300432251. The next prime is 13122300432301. The reversal of 13122300432255 is 55223400322131.
It is not a de Polignac number, because 13122300432255 - 22 = 13122300432251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122300432251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27396787 + ... + 27871643.
It is an arithmetic number, because the mean of its divisors is an integer number (749850167232).
Almost surely, 213122300432255 is an apocalyptic number.
13122300432255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13122300432255 is a deficient number, since it is larger than the sum of its proper divisors (10872904919169).
13122300432255 is a wasteful number, since it uses less digits than its factorization.
13122300432255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738055.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 13122300432255 its reverse (55223400322131), we get a palindrome (68345700754386).
The spelling of 13122300432255 in words is "thirteen trillion, one hundred twenty-two billion, three hundred million, four hundred thirty-two thousand, two hundred fifty-five".
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