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1312230234343 = 7187461462049
BaseRepresentation
bin10011000110000111000…
…001000101100011100111
311122110002120200201201111
4103012013001011203213
5132444421414444333
62442455200005451
7163543200645310
oct23060701054347
94573076621644
101312230234343
11466571837286
1219239b300887
1396986b70ab2
14477259b9607
15242029c34cd
hex131870458e7

1312230234343 has 4 divisors (see below), whose sum is σ = 1499691696400. Its totient is φ = 1124768772288.

The previous prime is 1312230234319. The next prime is 1312230234353. The reversal of 1312230234343 is 3434320322131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-1312230234343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312230234353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93730731018 + ... + 93730731031.

It is an arithmetic number, because the mean of its divisors is an integer number (374922924100).

Almost surely, 21312230234343 is an apocalyptic number.

1312230234343 is a deficient number, since it is larger than the sum of its proper divisors (187461462057).

1312230234343 is an equidigital number, since it uses as much as digits as its factorization.

1312230234343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187461462056.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1312230234343 its reverse (3434320322131), we get a palindrome (4746550556474).

The spelling of 1312230234343 in words is "one trillion, three hundred twelve billion, two hundred thirty million, two hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 7 187461462049 1312230234343