Base | Representation |
---|---|
bin | 11101110101100010111110… |
… | …010010010100010101110100 |
3 | 122012121210120210221021211001 |
4 | 131311202332102110111310 |
5 | 114144424233011102330 |
6 | 1143031010154053044 |
7 | 36432360044216602 |
oct | 3565427622242564 |
9 | 565553523837731 |
10 | 131223033300340 |
11 | 388a2415358823 |
12 | 12873aa041a184 |
13 | 582b381abb297 |
14 | 245932b7a2872 |
15 | 102862b4709ca |
hex | 7758be494574 |
131223033300340 has 96 divisors (see below), whose sum is σ = 292164803280000. Its totient is φ = 49368185298432.
The previous prime is 131223033300329. The next prime is 131223033300341. The reversal of 131223033300340 is 43003330322131.
It is a junction number, because it is equal to n+sod(n) for n = 131223033300299 and 131223033300308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131223033300341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 112831326 + ... + 113988394.
It is an arithmetic number, because the mean of its divisors is an integer number (3043383367500).
Almost surely, 2131223033300340 is an apocalyptic number.
131223033300340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131223033300340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (146082401640000).
131223033300340 is an abundant number, since it is smaller than the sum of its proper divisors (160941769979660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131223033300340 is a wasteful number, since it uses less digits than its factorization.
131223033300340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1159249 (or 1159247 counting only the distinct ones).
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 131223033300340 its reverse (43003330322131), we get a palindrome (174226363622471).
The spelling of 131223033300340 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, thirty-three million, three hundred thousand, three hundred forty".
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