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131223033300340 = 2251914920031157069
BaseRepresentation
bin11101110101100010111110…
…010010010100010101110100
3122012121210120210221021211001
4131311202332102110111310
5114144424233011102330
61143031010154053044
736432360044216602
oct3565427622242564
9565553523837731
10131223033300340
11388a2415358823
1212873aa041a184
13582b381abb297
14245932b7a2872
15102862b4709ca
hex7758be494574

131223033300340 has 96 divisors (see below), whose sum is σ = 292164803280000. Its totient is φ = 49368185298432.

The previous prime is 131223033300329. The next prime is 131223033300341. The reversal of 131223033300340 is 43003330322131.

It is a junction number, because it is equal to n+sod(n) for n = 131223033300299 and 131223033300308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131223033300341) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 112831326 + ... + 113988394.

It is an arithmetic number, because the mean of its divisors is an integer number (3043383367500).

Almost surely, 2131223033300340 is an apocalyptic number.

131223033300340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131223033300340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (146082401640000).

131223033300340 is an abundant number, since it is smaller than the sum of its proper divisors (160941769979660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131223033300340 is a wasteful number, since it uses less digits than its factorization.

131223033300340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1159249 (or 1159247 counting only the distinct ones).

The product of its (nonzero) digits is 11664, while the sum is 28.

Adding to 131223033300340 its reverse (43003330322131), we get a palindrome (174226363622471).

The spelling of 131223033300340 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, thirty-three million, three hundred thousand, three hundred forty".

Divisors: 1 2 4 5 10 19 20 38 76 95 149 190 298 380 596 745 1490 2003 2831 2980 4006 5662 8012 10015 11324 14155 20030 28310 38057 40060 56620 76114 152228 190285 298447 380570 596894 761140 1157069 1193788 1492235 2314138 2984470 4628276 5670493 5785345 5968940 11340986 11570690 21984311 22681972 23141380 28352465 43968622 56704930 87937244 109921555 113409860 172403281 219843110 344806562 439686220 689613124 862016405 1724032810 2317609207 3275662339 3448065620 4635218414 6551324678 9270436828 11588046035 13102649356 16378311695 23176092070 32756623390 44034574933 46352184140 65513246780 88069149866 176138299732 220172874665 345323771843 440345749330 690647543686 880691498660 1381295087372 1726618859215 3453237718430 6561151665017 6906475436860 13122303330034 26244606660068 32805758325085 65611516650170 131223033300340