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13122320011 = 49992624989
BaseRepresentation
bin11000011100010011…
…01011011010001011
31020212111221220222021
430032021223122023
5203333303220021
610010040505311
7643116610513
oct141611533213
936774856867
1013122320011
115624231279
12266277b237
13131182b8c8
148c6aca843
1551c064c41
hex30e26b68b

13122320011 has 4 divisors (see below), whose sum is σ = 13124950000. Its totient is φ = 13119690024.

The previous prime is 13122319967. The next prime is 13122320023. The reversal of 13122320011 is 11002322131.

13122320011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122320011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13122324011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1307496 + ... + 1317493.

It is an arithmetic number, because the mean of its divisors is an integer number (3281237500).

Almost surely, 213122320011 is an apocalyptic number.

13122320011 is a deficient number, since it is larger than the sum of its proper divisors (2629989).

13122320011 is an equidigital number, since it uses as much as digits as its factorization.

13122320011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2629988.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13122320011 its reverse (11002322131), we get a palindrome (24124642142).

The spelling of 13122320011 in words is "thirteen billion, one hundred twenty-two million, three hundred twenty thousand, eleven".

Divisors: 1 4999 2624989 13122320011