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1312240420993 is a prime number
BaseRepresentation
bin10011000110000111100…
…111111100100010000001
311122110010021212021011211
4103012013213330202001
5132444432021432433
62442500202210121
7163543353353065
oct23060747744201
94573107767154
101312240420993
114665775646a7
121923a27b3941
1396988cc95b8
14477270abaa5
15242038368cd
hex131879fc881

1312240420993 has 2 divisors, whose sum is σ = 1312240420994. Its totient is φ = 1312240420992.

The previous prime is 1312240420969. The next prime is 1312240421033. The reversal of 1312240420993 is 3990240422131.

It is a happy number.

It is an a-pointer prime, because the next prime (1312240421033) can be obtained adding 1312240420993 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1261719767169 + 50520653824 = 1123263^2 + 224768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312240420993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312240420093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656120210496 + 656120210497.

It is an arithmetic number, because the mean of its divisors is an integer number (656120210497).

Almost surely, 21312240420993 is an apocalyptic number.

It is an amenable number.

1312240420993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312240420993 is an equidigital number, since it uses as much as digits as its factorization.

1312240420993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 40.

The spelling of 1312240420993 in words is "one trillion, three hundred twelve billion, two hundred forty million, four hundred twenty thousand, nine hundred ninety-three".