Base | Representation |
---|---|
bin | 1011111011110101001101… |
… | …0001110000100011100111 |
3 | 1201110111112010201220011211 |
4 | 2332331103101300203213 |
5 | 3204444411144103133 |
6 | 43524223053412251 |
7 | 2523033222515563 |
oct | 276752321604347 |
9 | 51414463656154 |
10 | 13122522253543 |
11 | 41aa25978827a |
12 | 157b29619a087 |
13 | 7425aa593cb1 |
14 | 3351c23326a3 |
15 | 17b530cb1bcd |
hex | bef534708e7 |
13122522253543 has 2 divisors, whose sum is σ = 13122522253544. Its totient is φ = 13122522253542.
The previous prime is 13122522253537. The next prime is 13122522253549. The reversal of 13122522253543 is 34535222522131.
It is a balanced prime because it is at equal distance from previous prime (13122522253537) and next prime (13122522253549).
It is a cyclic number.
It is not a de Polignac number, because 13122522253543 - 233 = 13113932318951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13122522253496 and 13122522253505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122522253549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561261126771 + 6561261126772.
It is an arithmetic number, because the mean of its divisors is an integer number (6561261126772).
Almost surely, 213122522253543 is an apocalyptic number.
13122522253543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122522253543 is an equidigital number, since it uses as much as digits as its factorization.
13122522253543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432000, while the sum is 40.
Adding to 13122522253543 its reverse (34535222522131), we get a palindrome (47657744775674).
The spelling of 13122522253543 in words is "thirteen trillion, one hundred twenty-two billion, five hundred twenty-two million, two hundred fifty-three thousand, five hundred forty-three".
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