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131230302013 = 592224242407
BaseRepresentation
bin111101000110111101…
…1110111111100111101
3110112201122222001201001
41322031323313330331
54122224424131023
6140141504450301
712324003106456
oct1721573677475
9415648861631
10131230302013
11507220a2258
1221524919991
13c4b4a485a5
1464cca4612d
153630d876ad
hex1e8def7f3d

131230302013 has 4 divisors (see below), whose sum is σ = 133454544480. Its totient is φ = 129006059548.

The previous prime is 131230302001. The next prime is 131230302017. The reversal of 131230302013 is 310203032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131230302013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131230302017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1112121145 + ... + 1112121262.

It is an arithmetic number, because the mean of its divisors is an integer number (33363636120).

Almost surely, 2131230302013 is an apocalyptic number.

It is an amenable number.

131230302013 is a deficient number, since it is larger than the sum of its proper divisors (2224242467).

131230302013 is an equidigital number, since it uses as much as digits as its factorization.

131230302013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2224242466.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 131230302013 its reverse (310203032131), we get a palindrome (441433334144).

The spelling of 131230302013 in words is "one hundred thirty-one billion, two hundred thirty million, three hundred two thousand, thirteen".

Divisors: 1 59 2224242407 131230302013