Base | Representation |
---|---|
bin | 10011000110001011111… |
… | …110111011001000100000 |
3 | 11122110022101110210000222 |
4 | 103012023332323020200 |
5 | 133000104232202230 |
6 | 2442511333502212 |
7 | 163545232104161 |
oct | 23061376731040 |
9 | 4573271423028 |
10 | 1312313553440 |
11 | 46660487513a |
12 | 1924031a1968 |
13 | 9699b1c3b36 |
14 | 47732aa7768 |
15 | 24209e806e5 |
hex | 1318bfbb220 |
1312313553440 has 48 divisors (see below), whose sum is σ = 3100505892120. Its totient is φ = 524897464320.
The previous prime is 1312313553373. The next prime is 1312313553461. The reversal of 1312313553440 is 443553132131.
It can be written as a sum of positive squares in 4 ways, for example, as 1271184091024 + 41129462416 = 1127468^2 + 202804^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1312313553440.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2937176 + ... + 3354344.
Almost surely, 21312313553440 is an apocalyptic number.
1312313553440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1312313553440 is an abundant number, since it is smaller than the sum of its proper divisors (1788192338680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312313553440 is a wasteful number, since it uses less digits than its factorization.
1312313553440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436845 (or 436837 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 1312313553440 its reverse (443553132131), we get a palindrome (1755866685571).
The spelling of 1312313553440 in words is "one trillion, three hundred twelve billion, three hundred thirteen million, five hundred fifty-three thousand, four hundred forty".
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