Base | Representation |
---|---|
bin | 1011111011110111110001… |
… | …0001011000100011101111 |
3 | 1201110120022001220002220102 |
4 | 2332331330101120203233 |
5 | 3210002313231133403 |
6 | 43524415222541315 |
7 | 2523056243452040 |
oct | 276757421304357 |
9 | 51416261802812 |
10 | 13123210021103 |
11 | 41aa581a32216 |
12 | 157b44859783b |
13 | 742689c0c650 |
14 | 3352498048c7 |
15 | 17b571369b88 |
hex | bef7c4588ef |
13123210021103 has 16 divisors (see below), whose sum is σ = 16152487228416. Its totient is φ = 10382656485600.
The previous prime is 13123210021093. The next prime is 13123210021211. The reversal of 13123210021103 is 30112001232131.
It is a happy number.
It is not a de Polignac number, because 13123210021103 - 226 = 13123142912239 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13123210021403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2013173 + ... + 5504478.
It is an arithmetic number, because the mean of its divisors is an integer number (1009530451776).
Almost surely, 213123210021103 is an apocalyptic number.
13123210021103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13123210021103 is a deficient number, since it is larger than the sum of its proper divisors (3029277207313).
13123210021103 is a wasteful number, since it uses less digits than its factorization.
13123210021103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7536854.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13123210021103 its reverse (30112001232131), we get a palindrome (43235211253234).
The spelling of 13123210021103 in words is "thirteen trillion, one hundred twenty-three billion, two hundred ten million, twenty-one thousand, one hundred three".
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