Base | Representation |
---|---|
bin | 11000011100011010… |
… | …00111011011110001 |
3 | 1020212120122201012212 |
4 | 30032031013123301 |
5 | 203334021034413 |
6 | 10010112101505 |
7 | 643130353133 |
oct | 141615073361 |
9 | 36776581185 |
10 | 13123221233 |
11 | 5624797391 |
12 | 2662b34895 |
13 | 1311a85b85 |
14 | 8c6c83053 |
15 | 51c191ca8 |
hex | 30e3476f1 |
13123221233 has 4 divisors (see below), whose sum is σ = 13125549168. Its totient is φ = 13120893300.
The previous prime is 13123221193. The next prime is 13123221253. The reversal of 13123221233 is 33212232131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33212232131 = 13 ⋅2554787087.
It is a cyclic number.
It is not a de Polignac number, because 13123221233 - 28 = 13123220977 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13123221199 and 13123221208.
It is not an unprimeable number, because it can be changed into a prime (13123221253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1155491 + ... + 1166792.
It is an arithmetic number, because the mean of its divisors is an integer number (3281387292).
Almost surely, 213123221233 is an apocalyptic number.
It is an amenable number.
13123221233 is a deficient number, since it is larger than the sum of its proper divisors (2327935).
13123221233 is an equidigital number, since it uses as much as digits as its factorization.
13123221233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2327934.
The product of its digits is 1296, while the sum is 23.
Adding to 13123221233 its reverse (33212232131), we get a palindrome (46335453364).
The spelling of 13123221233 in words is "thirteen billion, one hundred twenty-three million, two hundred twenty-one thousand, two hundred thirty-three".
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