Base | Representation |
---|---|
bin | 111101000111000001… |
… | …1111000111100100011 |
3 | 110112201210220211001002 |
4 | 1322032003320330203 |
5 | 4122230443400420 |
6 | 140142021502215 |
7 | 12324030010463 |
oct | 1721603707443 |
9 | 415653824032 |
10 | 131232403235 |
11 | 507232a79aa |
12 | 2152557196b |
13 | c4b5302b0b |
14 | 64cd031ba3 |
15 | 3631150075 |
hex | 1e8e0f8f23 |
131232403235 has 4 divisors (see below), whose sum is σ = 157478883888. Its totient is φ = 104985922584.
The previous prime is 131232403231. The next prime is 131232403241. The reversal of 131232403235 is 532304232131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 532304232131 = 7 ⋅76043461733.
It is a cyclic number.
It is not a de Polignac number, because 131232403235 - 22 = 131232403231 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131232403198 and 131232403207.
It is not an unprimeable number, because it can be changed into a prime (131232403231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13123240319 + ... + 13123240328.
It is an arithmetic number, because the mean of its divisors is an integer number (39369720972).
Almost surely, 2131232403235 is an apocalyptic number.
131232403235 is a deficient number, since it is larger than the sum of its proper divisors (26246480653).
131232403235 is an equidigital number, since it uses as much as digits as its factorization.
131232403235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26246480652.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 131232403235 its reverse (532304232131), we get a palindrome (663536635366).
The spelling of 131232403235 in words is "one hundred thirty-one billion, two hundred thirty-two million, four hundred three thousand, two hundred thirty-five".
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