Base | Representation |
---|---|
bin | 1011111011111000000111… |
… | …0001011101000000111111 |
3 | 1201110120112111120002000121 |
4 | 2332332001301131000333 |
5 | 3210003010343022142 |
6 | 43524432321035411 |
7 | 2523061444104502 |
oct | 276760161350077 |
9 | 51416474502017 |
10 | 13123302314047 |
11 | 41aa61a03a282 |
12 | 157b473485b67 |
13 | 7426a3085163 |
14 | 335257b8b139 |
15 | 17b5794eac67 |
hex | bef81c5d03f |
13123302314047 has 2 divisors, whose sum is σ = 13123302314048. Its totient is φ = 13123302314046.
The previous prime is 13123302313981. The next prime is 13123302314081. The reversal of 13123302314047 is 74041320332131.
It is an a-pointer prime, because the next prime (13123302314081) can be obtained adding 13123302314047 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123302314047 - 235 = 13088942575679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123302314347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561651157023 + 6561651157024.
It is an arithmetic number, because the mean of its divisors is an integer number (6561651157024).
Almost surely, 213123302314047 is an apocalyptic number.
13123302314047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123302314047 is an equidigital number, since it uses as much as digits as its factorization.
13123302314047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 13123302314047 its reverse (74041320332131), we get a palindrome (87164622646178).
The spelling of 13123302314047 in words is "thirteen trillion, one hundred twenty-three billion, three hundred two million, three hundred fourteen thousand, forty-seven".
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