131233130211340 has 24 divisors (see below), whose sum is σ = 275623268563440. Its totient is φ = 52486833966528.

The previous prime is 131233130211329. The next prime is 131233130211353. The reversal of 131233130211340 is 43112031332131.

It is a junction number, because it is equal to n+sod(n) for n = 131233130211299 and 131233130211308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 400964707 + ... + 401291866.

It is an arithmetic number, because the mean of its divisors is an integer number (11484302856810).

Almost surely, 2^{131233130211340} is an apocalyptic number.

131233130211340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131233130211340 is an abundant number, since it is smaller than the sum of its proper divisors (144390138352100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131233130211340 is a wasteful number, since it uses less digits than its factorization.

131233130211340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802264761 (or 802264759 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 131233130211340 its reverse (43112031332131), we get a palindrome (174345161543471).

The spelling of 131233130211340 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred thirty million, two hundred eleven thousand, three hundred forty".