131233140130035 has 32 divisors (see below), whose sum is σ = 221027403317760. Its totient is φ = 66306320610048.

The previous prime is 131233140130033. The next prime is 131233140130151. The reversal of 131233140130035 is 530031041332131.

It is a happy number.

It is not a de Polignac number, because 131233140130035 - 2¹ = 131233140130033 is a prime.

It is a super-3 number, since 3×131233140130035³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131233140129984 and 131233140130011.

It is not an unprimeable number, because it can be changed into a prime (131233140130033) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16839034 + ... + 23367056.

It is an arithmetic number, because the mean of its divisors is an integer number (6907106353680).

Almost surely, 2^{131233140130035} is an apocalyptic number.

131233140130035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131233140130035 is a deficient number, since it is larger than the sum of its proper divisors (89794263187725).

131233140130035 is a wasteful number, since it uses less digits than its factorization.

131233140130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6598587.

The product of its (nonzero) digits is 9720, while the sum is 30.

Adding to 131233140130035 its reverse (530031041332131), we get a palindrome (661264181462166).

The spelling of 131233140130035 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred forty million, one hundred thirty thousand, thirty-five".