1312341140471 has 2 divisors, whose sum is σ = 1312341140472. Its totient is φ = 1312341140470.

The previous prime is 1312341140423. The next prime is 1312341140503. The reversal of 1312341140471 is 1740411432131.

It is an a-pointer prime, because the next prime (1312341140503) can be obtained adding 1312341140471 to its sum of digits (32).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312341140471 - 2¹⁸ = 1312340878327 is a prime.

It is a super-3 number, since 3×1312341140471³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312341140771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656170570235 + 656170570236.

It is an arithmetic number, because the mean of its divisors is an integer number (656170570236).

Almost surely, 2^{1312341140471} is an apocalyptic number.

1312341140471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312341140471 is an equidigital number, since it uses as much as digits as its factorization.

1312341140471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 32.

The spelling of 1312341140471 in words is "one trillion, three hundred twelve billion, three hundred forty-one million, one hundred forty thousand, four hundred seventy-one".