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1312343520123 = 3848695154389
BaseRepresentation
bin10011000110001101110…
…001001111001101111011
311122110101110212020121010
4103012031301033031323
5133000134420120443
62442514324045003
7163546044603456
oct23061561171573
94573343766533
101312343520123
1146661a782599
12192411233763
13969a44868bc
1447736a6849d
152420c8ee733
hex1318dc4f37b

1312343520123 has 8 divisors (see below), whose sum is σ = 1749812317200. Its totient is φ = 874885201568.

The previous prime is 1312343520097. The next prime is 1312343520197. The reversal of 1312343520123 is 3210253432131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1312343520123 - 210 = 1312343519099 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1312343520823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2322588 + ... + 2831801.

It is an arithmetic number, because the mean of its divisors is an integer number (218726539650).

Almost surely, 21312343520123 is an apocalyptic number.

1312343520123 is a deficient number, since it is larger than the sum of its proper divisors (437468797077).

1312343520123 is an equidigital number, since it uses as much as digits as its factorization.

1312343520123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5239261.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 1312343520123 its reverse (3210253432131), we get a palindrome (4522596952254).

The spelling of 1312343520123 in words is "one trillion, three hundred twelve billion, three hundred forty-three million, five hundred twenty thousand, one hundred twenty-three".

Divisors: 1 3 84869 254607 5154389 15463167 437447840041 1312343520123