Base | Representation |
---|---|
bin | 1011111011111000100111… |
… | …1111100100011101101111 |
3 | 1201110120220010002001022011 |
4 | 2332332021333210131233 |
5 | 3210003301144413203 |
6 | 43524454125102051 |
7 | 2523065040304522 |
oct | 276761177443557 |
9 | 51416803061264 |
10 | 13123440232303 |
11 | 41aa68a97a305 |
12 | 157b4b16b7927 |
13 | 7426c5813aab |
14 | 33526c20cbb9 |
15 | 17b58669076d |
hex | bef89fe476f |
13123440232303 has 2 divisors, whose sum is σ = 13123440232304. Its totient is φ = 13123440232302.
The previous prime is 13123440232289. The next prime is 13123440232349. The reversal of 13123440232303 is 30323204432131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123440232303 - 233 = 13114850297711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123440232363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561720116151 + 6561720116152.
It is an arithmetic number, because the mean of its divisors is an integer number (6561720116152).
Almost surely, 213123440232303 is an apocalyptic number.
13123440232303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123440232303 is an equidigital number, since it uses as much as digits as its factorization.
13123440232303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13123440232303 its reverse (30323204432131), we get a palindrome (43446644664434).
The spelling of 13123440232303 in words is "thirteen trillion, one hundred twenty-three billion, four hundred forty million, two hundred thirty-two thousand, three hundred three".
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