Base | Representation |
---|---|
bin | 111101000111000111… |
… | …0010110110100101111 |
3 | 110112202000002012212001 |
4 | 1322032032112310233 |
5 | 4122232144201210 |
6 | 140142200353131 |
7 | 12324062226115 |
oct | 1721616266457 |
9 | 415660065761 |
10 | 131235147055 |
11 | 50724901421 |
12 | 215264757a7 |
13 | c4b5a5398c |
14 | 64cd547ab5 |
15 | 36314e303a |
hex | 1e8e396d2f |
131235147055 has 4 divisors (see below), whose sum is σ = 157482176472. Its totient is φ = 104988117640.
The previous prime is 131235147053. The next prime is 131235147073. The reversal of 131235147055 is 550741532131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131235147055 - 21 = 131235147053 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131235147053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13123514701 + ... + 13123514710.
It is an arithmetic number, because the mean of its divisors is an integer number (39370544118).
Almost surely, 2131235147055 is an apocalyptic number.
131235147055 is a deficient number, since it is larger than the sum of its proper divisors (26247029417).
131235147055 is an equidigital number, since it uses as much as digits as its factorization.
131235147055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26247029416.
The product of its (nonzero) digits is 63000, while the sum is 37.
Adding to 131235147055 its reverse (550741532131), we get a palindrome (681976679186).
The spelling of 131235147055 in words is "one hundred thirty-one billion, two hundred thirty-five million, one hundred forty-seven thousand, fifty-five".
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