Base | Representation |
---|---|
bin | 111101000111001111… |
… | …1010010000110001111 |
3 | 110112202022102122101122 |
4 | 1322032133102012033 |
5 | 4122234313143033 |
6 | 140142435431155 |
7 | 12324145026203 |
oct | 1721637220617 |
9 | 415668378348 |
10 | 131239584143 |
11 | 50727362038 |
12 | 21527a554bb |
13 | c4b6948485 |
14 | 64cdd80b03 |
15 | 3631abca98 |
hex | 1e8e7d218f |
131239584143 has 2 divisors, whose sum is σ = 131239584144. Its totient is φ = 131239584142.
The previous prime is 131239584097. The next prime is 131239584191. The reversal of 131239584143 is 341485932131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (341485932131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131239584143 - 214 = 131239567759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131239584094 and 131239584103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131239584643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65619792071 + 65619792072.
It is an arithmetic number, because the mean of its divisors is an integer number (65619792072).
Almost surely, 2131239584143 is an apocalyptic number.
131239584143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131239584143 is an equidigital number, since it uses as much as digits as its factorization.
131239584143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 44.
The spelling of 131239584143 in words is "one hundred thirty-one billion, two hundred thirty-nine million, five hundred eighty-four thousand, one hundred forty-three".
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