Base | Representation |
---|---|
bin | 111101000111010001… |
… | …1010100111000110111 |
3 | 110112202101102111110012 |
4 | 1322032203110320313 |
5 | 4122240101103101 |
6 | 140142514250435 |
7 | 12324160032461 |
oct | 1721643247067 |
9 | 415671374405 |
10 | 131240644151 |
11 | 50727a16481 |
12 | 21528286a1b |
13 | c4b6c29ab6 |
14 | 64d0179131 |
15 | 3631c2bbbb |
hex | 1e8e8d4e37 |
131240644151 has 2 divisors, whose sum is σ = 131240644152. Its totient is φ = 131240644150.
The previous prime is 131240644121. The next prime is 131240644153. The reversal of 131240644151 is 151446042131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131240644151 is a prime.
Together with 131240644153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131240644153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620322075 + 65620322076.
It is an arithmetic number, because the mean of its divisors is an integer number (65620322076).
Almost surely, 2131240644151 is an apocalyptic number.
131240644151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131240644151 is an equidigital number, since it uses as much as digits as its factorization.
131240644151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 131240644151 its reverse (151446042131), we get a palindrome (282686686282).
The spelling of 131240644151 in words is "one hundred thirty-one billion, two hundred forty million, six hundred forty-four thousand, one hundred fifty-one".
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