Base | Representation |
---|---|
bin | 100111000111001… |
… | …1100101100010111 |
3 | 10101110112100121021 |
4 | 1032032130230113 |
5 | 10141434113031 |
6 | 334121302011 |
7 | 44344206235 |
oct | 11616345427 |
9 | 3343470537 |
10 | 1312410391 |
11 | 613904396 |
12 | 307634907 |
13 | 17bb919c6 |
14 | c6431955 |
15 | 7a342511 |
hex | 4e39cb17 |
1312410391 has 4 divisors (see below), whose sum is σ = 1312673472. Its totient is φ = 1312147312.
The previous prime is 1312410361. The next prime is 1312410409. The reversal of 1312410391 is 1930142131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1930142131 = 2591 ⋅744941.
It is a cyclic number.
It is not a de Polignac number, because 1312410391 - 27 = 1312410263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312410361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123910 + ... + 134083.
It is an arithmetic number, because the mean of its divisors is an integer number (328168368).
Almost surely, 21312410391 is an apocalyptic number.
1312410391 is a deficient number, since it is larger than the sum of its proper divisors (263081).
1312410391 is an equidigital number, since it uses as much as digits as its factorization.
1312410391 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263080.
The product of its (nonzero) digits is 648, while the sum is 25.
The square root of 1312410391 is about 36227.2051226699. The cubic root of 1312410391 is about 1094.8548673045.
The spelling of 1312410391 in words is "one billion, three hundred twelve million, four hundred ten thousand, three hundred ninety-one".
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