1312411050533 has 4 divisors (see below), whose sum is σ = 1431721146048. Its totient is φ = 1193100955020.

The previous prime is 1312411050491. The next prime is 1312411050539. The reversal of 1312411050533 is 3350501142131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312411050533 - 2⁶ = 1312411050469 is a prime.

It is a super-2 number, since 2×1312411050533² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1312411050496 and 1312411050505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312411050539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59655047741 + ... + 59655047762.

It is an arithmetic number, because the mean of its divisors is an integer number (357930286512).

Almost surely, 2^{1312411050533} is an apocalyptic number.

It is an amenable number.

1312411050533 is a deficient number, since it is larger than the sum of its proper divisors (119310095515).

1312411050533 is a wasteful number, since it uses less digits than its factorization.

1312411050533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119310095514.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 1312411050533 its reverse (3350501142131), we get a palindrome (4662912192664).

The spelling of 1312411050533 in words is "one trillion, three hundred twelve billion, four hundred eleven million, fifty thousand, five hundred thirty-three".