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1312412142131 = 1777200714243
BaseRepresentation
bin10011000110010001110…
…111000000101000110011
311122110120020222121021222
4103012101313000220303
5133000310002022011
62442525214535255
7163550540100566
oct23062167005063
94573506877258
101312412142131
114666554922a2
1219243020752b
13969b576213c
1447741c0c4dd
1524213956ddb
hex13191dc0a33

1312412142131 has 4 divisors (see below), whose sum is σ = 1389612856392. Its totient is φ = 1235211427872.

The previous prime is 1312412142121. The next prime is 1312412142137.

It is a happy number.

1312412142131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312412142131 - 210 = 1312412141107 is a prime.

It is a super-2 number, since 2×13124121421312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312412142131.

It is not an unprimeable number, because it can be changed into a prime (1312412142137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38600357105 + ... + 38600357138.

It is an arithmetic number, because the mean of its divisors is an integer number (347403214098).

Almost surely, 21312412142131 is an apocalyptic number.

1312412142131 is a deficient number, since it is larger than the sum of its proper divisors (77200714261).

1312412142131 is an equidigital number, since it uses as much as digits as its factorization.

1312412142131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77200714260.

The product of its digits is 1152, while the sum is 26.

The spelling of 1312412142131 in words is "one trillion, three hundred twelve billion, four hundred twelve million, one hundred forty-two thousand, one hundred thirty-one".

Divisors: 1 17 77200714243 1312412142131