Base | Representation |
---|---|
bin | 1011111011111011011101… |
… | …0110100110011011011111 |
3 | 1201110122212011001110121202 |
4 | 2332332313112212123133 |
5 | 3210011331004310013 |
6 | 43525101432150115 |
7 | 2523122640636605 |
oct | 276766726463337 |
9 | 51418764043552 |
10 | 13124201244383 |
11 | 41aaa40500a09 |
12 | 157b68453833b |
13 | 7427b73959b8 |
14 | 335301309875 |
15 | 17b5cd3b5858 |
hex | befb75a66df |
13124201244383 has 2 divisors, whose sum is σ = 13124201244384. Its totient is φ = 13124201244382.
The previous prime is 13124201244299. The next prime is 13124201244431. The reversal of 13124201244383 is 38344210242131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13124201244383 - 212 = 13124201240287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124201234383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562100622191 + 6562100622192.
It is an arithmetic number, because the mean of its divisors is an integer number (6562100622192).
Almost surely, 213124201244383 is an apocalyptic number.
13124201244383 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124201244383 is an equidigital number, since it uses as much as digits as its factorization.
13124201244383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 38.
The spelling of 13124201244383 in words is "thirteen trillion, one hundred twenty-four billion, two hundred one million, two hundred forty-four thousand, three hundred eighty-three".
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