13124201244431 has 2 divisors, whose sum is σ = 13124201244432. Its totient is φ = 13124201244430.

The previous prime is 13124201244383. The next prime is 13124201244437. The reversal of 13124201244431 is 13444210242131.

It is a strong prime.

It is an emirp because it is prime and its reverse (13444210242131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124201244431 - 2¹⁰ = 13124201243407 is a prime.

It is a super-2 number, since 2×13124201244431² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124201244437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562100622215 + 6562100622216.

It is an arithmetic number, because the mean of its divisors is an integer number (6562100622216).

Almost surely, 2^{13124201244431} is an apocalyptic number.

13124201244431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124201244431 is an equidigital number, since it uses as much as digits as its factorization.

13124201244431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 13124201244431 its reverse (13444210242131), we get a palindrome (26568411486562).

The spelling of 13124201244431 in words is "thirteen trillion, one hundred twenty-four billion, two hundred one million, two hundred forty-four thousand, four hundred thirty-one".