13124204021112 has 64 divisors (see below), whose sum is σ = 33441281049600. Its totient is φ = 4291031418240.

The previous prime is 13124204021011. The next prime is 13124204021213. The reversal of 13124204021112 is 21112040242131.

It is an interprime number because it is at equal distance from previous prime (13124204021011) and next prime (13124204021213).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11959968 + ... + 13011119.

It is an arithmetic number, because the mean of its divisors is an integer number (522520016400).

Almost surely, 2^{13124204021112} is an apocalyptic number.

13124204021112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13124204021112 is an abundant number, since it is smaller than the sum of its proper divisors (20317077028488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13124204021112 is a wasteful number, since it uses less digits than its factorization.

13124204021112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24971516 (or 24971512 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 13124204021112 its reverse (21112040242131), we get a palindrome (34236244263243).

The spelling of 13124204021112 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, twenty-one thousand, one hundred twelve".