Search a number
-
+
131242150749167 is a prime number
BaseRepresentation
bin11101110101110100110001…
…110001100110001111101111
3122012200121221010210022110022
4131311310301301212033233
5114200232411042433132
61143043451155232355
736433634561650163
oct3565646161461757
9565617833708408
10131242150749167
11388aa535693007
12128777368a86bb
13583010a69b693
14245a222790ca3
151028d999a9e12
hex775d31c663ef

131242150749167 has 2 divisors, whose sum is σ = 131242150749168. Its totient is φ = 131242150749166.

The previous prime is 131242150749113. The next prime is 131242150749179. The reversal of 131242150749167 is 761947051242131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131242150749167 - 226 = 131242083640303 is a prime.

It is a super-2 number, since 2×1312421507491672 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131242150749107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621075374583 + 65621075374584.

It is an arithmetic number, because the mean of its divisors is an integer number (65621075374584).

Almost surely, 2131242150749167 is an apocalyptic number.

131242150749167 is a deficient number, since it is larger than the sum of its proper divisors (1).

131242150749167 is an equidigital number, since it uses as much as digits as its factorization.

131242150749167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 131242150749167 in words is "one hundred thirty-one trillion, two hundred forty-two billion, one hundred fifty million, seven hundred forty-nine thousand, one hundred sixty-seven".