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13124255455541 = 31423363079211
BaseRepresentation
bin1011111011111011101010…
…0101011001100100110101
31201110122222221001200100102
42332332322211121210311
53210011433344034131
643525111050123445
72523124166503616
oct276767245314465
951418887050312
1013124255455541
1141aaa6906861a
12157b69a720585
137427c5696ac9
143353085bbc0d
1517b5d30231cb
hexbefba959935

13124255455541 has 4 divisors (see below), whose sum is σ = 13547618534784. Its totient is φ = 12700892376300.

The previous prime is 13124255455529. The next prime is 13124255455573. The reversal of 13124255455541 is 14555455242131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124255455541 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124255655541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211681539575 + ... + 211681539636.

It is an arithmetic number, because the mean of its divisors is an integer number (3386904633696).

Almost surely, 213124255455541 is an apocalyptic number.

It is an amenable number.

13124255455541 is a deficient number, since it is larger than the sum of its proper divisors (423363079243).

13124255455541 is an equidigital number, since it uses as much as digits as its factorization.

13124255455541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 423363079242.

The product of its digits is 2400000, while the sum is 47.

The spelling of 13124255455541 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fifty-five million, four hundred fifty-five thousand, five hundred forty-one".

Divisors: 1 31 423363079211 13124255455541