Base | Representation |
---|---|
bin | 1011111011111011110101… |
… | …1011100100101110101011 |
3 | 1201110200010020220221010020 |
4 | 2332332331123210232223 |
5 | 3210012033110231220 |
6 | 43525115513451523 |
7 | 2523125316433623 |
oct | 276767533445653 |
9 | 51420106827106 |
10 | 13124303211435 |
11 | 41aaa930162a9 |
12 | 157b6b2710ba3 |
13 | 742802547930 |
14 | 335310a8d883 |
15 | 17b5d7308040 |
hex | befbd6e4bab |
13124303211435 has 32 divisors (see below), whose sum is σ = 22618527113280. Its totient is φ = 6459954536448.
The previous prime is 13124303211433. The next prime is 13124303211451. The reversal of 13124303211435 is 53411230342131.
It is not a de Polignac number, because 13124303211435 - 21 = 13124303211433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13124303211396 and 13124303211405.
It is not an unprimeable number, because it can be changed into a prime (13124303211433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5444614 + ... + 7476123.
It is an arithmetic number, because the mean of its divisors is an integer number (706828972290).
Almost surely, 213124303211435 is an apocalyptic number.
13124303211435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13124303211435 is a deficient number, since it is larger than the sum of its proper divisors (9494223901845).
13124303211435 is a wasteful number, since it uses less digits than its factorization.
13124303211435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12925967.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 13124303211435 its reverse (53411230342131), we get a palindrome (66535533553566).
The spelling of 13124303211435 in words is "thirteen trillion, one hundred twenty-four billion, three hundred three million, two hundred eleven thousand, four hundred thirty-five".
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