1312432441330 has 8 divisors (see below), whose sum is σ = 2362378394412. Its totient is φ = 524972976528.

The previous prime is 1312432441301. The next prime is 1312432441351. The reversal of 1312432441330 is 331442342131.

It can be written as a sum of positive squares in 2 ways, for example, as 1297929297289 + 14503144041 = 1139267^2 + 120429^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1312432441292 and 1312432441301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65621622057 + ... + 65621622076.

Almost surely, 2^{1312432441330} is an apocalyptic number.

1312432441330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1312432441330 is a deficient number, since it is larger than the sum of its proper divisors (1049945953082).

1312432441330 is a wasteful number, since it uses less digits than its factorization.

1312432441330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131243244140.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1312432441330 its reverse (331442342131), we get a palindrome (1643874783461).

The spelling of 1312432441330 in words is "one trillion, three hundred twelve billion, four hundred thirty-two million, four hundred forty-one thousand, three hundred thirty".