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131244013 = 216160733
BaseRepresentation
bin1111101001010…
…01111111101101
3100010221212221101
413310221333231
5232044302023
621005003101
73152361415
oct764517755
9303855841
10131244013
11680a162a
1237b53491
1321262aa4
1413605645
15b7c71ad
hex7d29fed

131244013 has 4 divisors (see below), whose sum is σ = 131306908. Its totient is φ = 131181120.

The previous prime is 131244011. The next prime is 131244019. The reversal of 131244013 is 310442131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 310442131 = 349889519.

It can be written as a sum of positive squares in 2 ways, for example, as 66634569 + 64609444 = 8163^2 + 8038^2 .

It is a cyclic number.

It is not a de Polignac number, because 131244013 - 21 = 131244011 is a prime.

It is a super-3 number, since 3×1312440133 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131244011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28206 + ... + 32527.

It is an arithmetic number, because the mean of its divisors is an integer number (32826727).

Almost surely, 2131244013 is an apocalyptic number.

It is an amenable number.

131244013 is a deficient number, since it is larger than the sum of its proper divisors (62895).

131244013 is an equidigital number, since it uses as much as digits as its factorization.

131244013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62894.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 131244013 is about 11456.1779403080. The cubic root of 131244013 is about 508.1904510963.

Adding to 131244013 its product of nonzero digits (288), we get a triangular number (131244301 = T16201).

Adding to 131244013 its reverse (310442131), we get a palindrome (441686144).

The spelling of 131244013 in words is "one hundred thirty-one million, two hundred forty-four thousand, thirteen".

Divisors: 1 2161 60733 131244013