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13124404311209 = 67611941192769
BaseRepresentation
bin1011111011111100001101…
…1101001111010010101001
31201110200101022011022221022
42332333003131033102221
53210012240000424314
643525133524422225
72523130654656302
oct276770335172251
951420338138838
1013124404311209
114200035099034
12157b720547975
1374281a484b99
143353202897a9
1517b5e112878e
hexbefc374f4a9

13124404311209 has 4 divisors (see below), whose sum is σ = 13126345510740. Its totient is φ = 13122463111680.

The previous prime is 13124404311199. The next prime is 13124404311211. The reversal of 13124404311209 is 90211340442131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8909299674025 + 4215104637184 = 2984845^2 + 2053072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124404311209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124404311229) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 970589624 + ... + 970603145.

It is an arithmetic number, because the mean of its divisors is an integer number (3281586377685).

Almost surely, 213124404311209 is an apocalyptic number.

It is an amenable number.

13124404311209 is a deficient number, since it is larger than the sum of its proper divisors (1941199531).

13124404311209 is an equidigital number, since it uses as much as digits as its factorization.

13124404311209 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1941199530.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 13124404311209 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, three hundred eleven thousand, two hundred nine".

Divisors: 1 6761 1941192769 13124404311209