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1312440431130 = 2325592111171393
BaseRepresentation
bin10011000110010011100…
…010111011001000011010
311122110122020012211111200
4103012103202323020122
5133000334222244010
62442532105135030
7163551332412033
oct23062342731032
94573566184450
101312440431130
1146666a454234
1219243978a476
13969bb5883aa
1447745893a8a
1524216193cc0
hex131938bb21a

1312440431130 has 96 divisors (see below), whose sum is σ = 3486630813120. Its totient is φ = 342421309440.

The previous prime is 1312440431101. The next prime is 1312440431177. The reversal of 1312440431130 is 311340442131.

1312440431130 is a `hidden beast` number, since 1 + 3 + 124 + 404 + 3 + 1 + 130 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 1312440431094 and 1312440431103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 534714 + ... + 1706106.

It is an arithmetic number, because the mean of its divisors is an integer number (36319070970).

Almost surely, 21312440431130 is an apocalyptic number.

1312440431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312440431130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1743315406560).

1312440431130 is an abundant number, since it is smaller than the sum of its proper divisors (2174190381990).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312440431130 is a wasteful number, since it uses less digits than its factorization.

1312440431130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1171676 (or 1171673 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1312440431130 its reverse (311340442131), we get a palindrome (1623780873261).

The spelling of 1312440431130 in words is "one trillion, three hundred twelve billion, four hundred forty million, four hundred thirty-one thousand, one hundred thirty".

Divisors: 1 2 3 5 6 9 10 15 18 30 45 59 90 118 177 211 295 354 422 531 590 633 885 1055 1062 1266 1770 1899 2110 2655 3165 3798 5310 6330 9495 12449 18990 24898 37347 62245 74694 112041 124490 186735 224082 373470 560205 1120410 1171393 2342786 3514179 5856965 7028358 10542537 11713930 17570895 21085074 35141790 52712685 69112187 105425370 138224374 207336561 247163923 345560935 414673122 494327846 622009683 691121870 741491769 1036682805 1235819615 1244019366 1482983538 2073365610 2224475307 2471639230 3110048415 3707458845 4448950614 6220096830 7414917690 11122376535 14582671457 22244753070 29165342914 43748014371 72913357285 87496028742 131244043113 145826714570 218740071855 262488086226 437480143710 656220215565 1312440431130