Base | Representation |
---|---|
bin | 10011000110010011100… |
… | …010111011001000011010 |
3 | 11122110122020012211111200 |
4 | 103012103202323020122 |
5 | 133000334222244010 |
6 | 2442532105135030 |
7 | 163551332412033 |
oct | 23062342731032 |
9 | 4573566184450 |
10 | 1312440431130 |
11 | 46666a454234 |
12 | 19243978a476 |
13 | 969bb5883aa |
14 | 47745893a8a |
15 | 24216193cc0 |
hex | 131938bb21a |
1312440431130 has 96 divisors (see below), whose sum is σ = 3486630813120. Its totient is φ = 342421309440.
The previous prime is 1312440431101. The next prime is 1312440431177. The reversal of 1312440431130 is 311340442131.
1312440431130 is a `hidden beast` number, since 1 + 3 + 124 + 404 + 3 + 1 + 130 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 1312440431094 and 1312440431103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 534714 + ... + 1706106.
It is an arithmetic number, because the mean of its divisors is an integer number (36319070970).
Almost surely, 21312440431130 is an apocalyptic number.
1312440431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1312440431130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1743315406560).
1312440431130 is an abundant number, since it is smaller than the sum of its proper divisors (2174190381990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312440431130 is a wasteful number, since it uses less digits than its factorization.
1312440431130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1171676 (or 1171673 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1312440431130 its reverse (311340442131), we get a palindrome (1623780873261).
The spelling of 1312440431130 in words is "one trillion, three hundred twelve billion, four hundred forty million, four hundred thirty-one thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •