Base | Representation |
---|---|
bin | 1011111011111100001110… |
… | …0000010010110101011011 |
3 | 1201110200101100200000121222 |
4 | 2332333003200102311123 |
5 | 3210012240202042110 |
6 | 43525133553522255 |
7 | 2523130664533361 |
oct | 276770340226533 |
9 | 51420340600558 |
10 | 13124405112155 |
11 | 4200035595877 |
12 | 157b72087338b |
13 | 74281a6a560c |
14 | 335320417631 |
15 | 17b5e1235c55 |
hex | befc3812d5b |
13124405112155 has 16 divisors (see below), whose sum is σ = 16285941640224. Its totient is φ = 10147667312640.
The previous prime is 13124405112139. The next prime is 13124405112173. The reversal of 13124405112155 is 55121150442131.
It is a happy number.
It is not a de Polignac number, because 13124405112155 - 24 = 13124405112139 is a prime.
It is a super-3 number, since 3×131244051121553 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 369579686 + ... + 369615195.
It is an arithmetic number, because the mean of its divisors is an integer number (1017871352514).
Almost surely, 213124405112155 is an apocalyptic number.
13124405112155 is a deficient number, since it is larger than the sum of its proper divisors (3161536528069).
13124405112155 is an equidigital number, since it uses as much as digits as its factorization.
13124405112155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 739195006.
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 13124405112155 its reverse (55121150442131), we get a palindrome (68245555554286).
The spelling of 13124405112155 in words is "thirteen trillion, one hundred twenty-four billion, four hundred five million, one hundred twelve thousand, one hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •