Base | Representation |
---|---|
bin | 1011111011111100010110… |
… | …1110010011111110110101 |
3 | 1201110200110221201110102020 |
4 | 2332333011232103332311 |
5 | 3210012324214410201 |
6 | 43525141403503353 |
7 | 2523131626141224 |
oct | 276770556237665 |
9 | 51420427643366 |
10 | 13124442341301 |
11 | 4200054603665 |
12 | 157b731227b59 |
13 | 74282530bbb5 |
14 | 335325348cbb |
15 | 17b5e463ba36 |
hex | befc5b93fb5 |
13124442341301 has 8 divisors (see below), whose sum is σ = 17972209332384. Its totient is φ = 8513151788880.
The previous prime is 13124442341299. The next prime is 13124442341357. The reversal of 13124442341301 is 10314324442131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13124442341301 - 21 = 13124442341299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13124442341501) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59119109535 + ... + 59119109756.
It is an arithmetic number, because the mean of its divisors is an integer number (2246526166548).
Almost surely, 213124442341301 is an apocalyptic number.
It is an amenable number.
13124442341301 is a deficient number, since it is larger than the sum of its proper divisors (4847766991083).
13124442341301 is a wasteful number, since it uses less digits than its factorization.
13124442341301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118238219331.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 13124442341301 its reverse (10314324442131), we get a palindrome (23438766783432).
The spelling of 13124442341301 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-two million, three hundred forty-one thousand, three hundred one".
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