Base | Representation |
---|---|
bin | 11000011100100110… |
… | …01011111110111111 |
3 | 1020212200122120100101 |
4 | 30032103023332333 |
5 | 203334423001420 |
6 | 10010210141531 |
7 | 643150032106 |
oct | 141623137677 |
9 | 36780576311 |
10 | 13124812735 |
11 | 5625684081 |
12 | 26635818a7 |
13 | 13121c23a8 |
14 | 8c717903d |
15 | 51c3a860a |
hex | 30e4cbfbf |
13124812735 has 4 divisors (see below), whose sum is σ = 15749775288. Its totient is φ = 10499850184.
The previous prime is 13124812733. The next prime is 13124812747. The reversal of 13124812735 is 53721842131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53721842131 = 6791 ⋅7910741.
It is a cyclic number.
It is not a de Polignac number, because 13124812735 - 21 = 13124812733 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13124812694 and 13124812703.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13124812733) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312481269 + ... + 1312481278.
It is an arithmetic number, because the mean of its divisors is an integer number (3937443822).
Almost surely, 213124812735 is an apocalyptic number.
13124812735 is a deficient number, since it is larger than the sum of its proper divisors (2624962553).
13124812735 is an equidigital number, since it uses as much as digits as its factorization.
13124812735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2624962552.
The product of its digits is 40320, while the sum is 37.
The spelling of 13124812735 in words is "thirteen billion, one hundred twenty-four million, eight hundred twelve thousand, seven hundred thirty-five".
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