Search a number
-
+
13124832845 = 52624966569
BaseRepresentation
bin11000011100100110…
…10000111001001101
31020212200200120221012
430032103100321031
5203334424122340
610010210415005
7643150144535
oct141623207115
936780616835
1013124832845
1156256981a3
122663591465
1313121cb5a7
148c71824c5
1551c3ae565
hex30e4d0e4d

13124832845 has 4 divisors (see below), whose sum is σ = 15749799420. Its totient is φ = 10499866272.

The previous prime is 13124832829. The next prime is 13124832883. The reversal of 13124832845 is 54823842131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54823842131 = 371481725463.

It can be written as a sum of positive squares in 2 ways, for example, as 7261255369 + 5863577476 = 85213^2 + 76574^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124832845 - 24 = 13124832829 is a prime.

It is a super-2 number, since 2×131248328452 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312483280 + ... + 1312483289.

It is an arithmetic number, because the mean of its divisors is an integer number (3937449855).

Almost surely, 213124832845 is an apocalyptic number.

It is an amenable number.

13124832845 is a deficient number, since it is larger than the sum of its proper divisors (2624966575).

13124832845 is an equidigital number, since it uses as much as digits as its factorization.

13124832845 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2624966574.

The product of its digits is 184320, while the sum is 41.

The spelling of 13124832845 in words is "thirteen billion, one hundred twenty-four million, eight hundred thirty-two thousand, eight hundred forty-five".

Divisors: 1 5 2624966569 13124832845