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13125103 is a prime number
BaseRepresentation
bin110010000100…
…010111101111
3220200211020221
4302010113233
511330000403
61145152211
7216363415
oct62042757
926624227
1013125103
1174550a2
12448b667
132947144
141a592b5
151243dbd
hexc845ef

13125103 has 2 divisors, whose sum is σ = 13125104. Its totient is φ = 13125102.

The previous prime is 13125089. The next prime is 13125107. The reversal of 13125103 is 30152131.

It is a strong prime.

It is an emirp because it is prime and its reverse (30152131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13125103 - 217 = 12994031 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13125107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562551 + 6562552.

It is an arithmetic number, because the mean of its divisors is an integer number (6562552).

Almost surely, 213125103 is an apocalyptic number.

13125103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125103 is an equidigital number, since it uses as much as digits as its factorization.

13125103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 13125103 is about 3622.8584018700. The cubic root of 13125103 is about 235.8853160586.

Adding to 13125103 its reverse (30152131), we get a palindrome (43277234).

The spelling of 13125103 in words is "thirteen million, one hundred twenty-five thousand, one hundred three".